Why is the /lounge/ here a nest of altright shitheads and not a group of sperglords talking about RedCream, milkribs and other loungelike topics.

>>2
I'm not calling you a nazi, Christopher. I'm just curious.

>>1
We have /SuperFratBoyExtreme/, /Shay/ and /Skankhunt42/ we don't need anymore shitting up our /lounge/.

HE has no style
HE has no grace
RedCream is a shitty failed meme

No RedCream, we have enough shills already without putting up with the fucking cuck crowd.

>>1
If you're already in a position where you're constantly concerned about being a "cuck," then you're doomed to the lifestyle you've been told you should hate yourself for.

I can already tell you're somebody who doesn't think for themselves or has any self confidence. I hope you understand how dangerous a combination that is. You are easily manipulated because you are probably stupid as well as unsure of yourself.

You're fucking doomed and so is society until you start thinking for yourself.

>>7

I can already tell you're somebody who doesn't think for themselves or has any self confidence. I hope you understand how dangerous a combination that is.

or
combination

nice logic cuckboy

>>9
Actually, sqrt(-1) is undefined, unless you are some degenerate structural engineer who defines i := sqrt(-1) and then moves on without understanding what's going on.
Normally, you define i as a number with the property i^2 = -1.
If you don't see the difference, get out

>>10
tfw I was taught that sqrt(-1)=i in american education

>>11
The reason why it does not work out is:
-1 = i^2 = sqrt(-1) * sqrt(-1) = sqrt((-1) * (-1)) =sqrt(1 * 1) = sqrt(1) = 1
To get around the contradiction above, you simply say "i is a number with the property i^2 = -1" and every calculation with i works properly.

>>12

i^2 = sqrt(-1) * sqrt(-1)

for an aparently intelligent person you sure failed to follow basic math rules. x^2 != sqrt(x) * sqrt(x), likewise for i.

>>13
Just because x^2 = -sqrt(x) * -sqrt(x)
is another valid solution does not make x^2 = sqrt(x) * sqrt(x) wrong.
The second equation still holds true and thus the chain of equations holds true (except for the intended contradiction).
You arbitrarily changed the the problem to 'find all solutions'.

>>13
stupid,
he never used x^2 = sqrt(x)^2..., he's right, you are the one who failed to follow some logic and simple equalities

>>13

x^2 != sqrt(x) * sqrt(x)

Please point to where you think I used that equation.

>>15
no.
i^2 is a negative value, i used the same concept but with a positive value variable to express the fact that squaring a square root will not be equal to squaring an integer.

x^2 = -sqrt(x) * -sqrt(x)

those negative came from nowhere anon. As mentioned above i used a positive value to express that the truth remains. Even if you make the integer value negative the truth remains that X squared does not equal the square of the root of X.

thus the chain of equations holds true

you expanded the chain without first seeing if the original equation was true. Here, do the same thing but instead apply it to an integer:
does the square of 2 equal the square of the square root of 2? 4 does not equal 2 anon, therefore you equation was wrong to begin with.

Please point to where you think I used that equation.

I provided an equivalent one to simplyfy the abstraction so that i can provide a proof with real integers as above.

>>17
btw just to make the burn worse. This is coming from someone with an IQ of 120 who has a constant C+ grade in mathematics.

>>17,18
Lovely burn anon, but x^2 = x * x

sqrt(x) * sqrt(x) = x

play with the signs all you want

>>19

but x^2 = x * x
sqrt(x) * sqrt(x) = x

that was the point i made anon. Other anon thought that x^2 = sqrt(x) * sqrt(x), so i debunked it for him.

>>17
>>18
Are you retarded or something? What does x^2 != sqrt(x) * sqrt(x) have to do with anything?
He never used x^2 = sqrt(x) * sqrt(x) in any of the steps so pointing out that it's false is irrelevant.

-1 = i^2 = sqrt(-1) * sqrt(-1) = sqrt((-1) * (-1)) =sqrt(1 * 1) = sqrt(1) = 1

These steps are either just using basic definitions or simple rules of operation of sqrt().
If you can't comprehend it, google it yourself you dumb shit.

>>20

Other anon thought that x^2 = sqrt(x) * sqrt(x), so i debunked it for him.

No he did not.
Point to the exact step where he assumed that this holds true.

>>21
I already explained that i used x as a placeholder for i do deabstractify the variable and thus allow me to show the proof in a more concise way.

He never used x^2 = sqrt(x) * sqrt(x)
i^2 = sqrt(-1) * sqrt(-1)

you just proved yourself wrong.

>>22

i^2 = sqrt(-1) * sqrt(-1)

i replaced 'i' with 'x'.

>>23
>>24
Are you this dumb?
It's you who assumes that i= -1. He wrote:
i^2 = sqrt(-1) * sqrt(-1)
Your 'abstract' rule x^2 = sqrt(x) * sqrt(x) would imply that he wrote
i^2 = sqrt(i) * sqrt(i)
which he did not

>>12
sqrt(i^2) = i
i * i = i^2
sqrt(i^2) * sqrt(i^2) = i^2
sqrt(i^2 * i^2) = i^4 = 1

This is not a contradiction, this is a universal truth in mathematics having to deal with imaginary numbers.

>>25
sorry i made a mistake in my logic.
backtracked and tried again. Found that his proof was right.
Problem was the assumption that the result was a contradiction.
What's more, sqrt(i^2) = sqrt(-1) so his original argument that sqrt(-1) is wrong is wrong.

see my reattempt here: >>26

>>27

Problem was the assumption that the result was a contradiction.

You moron, it was my intention to produce a contradiction.
The contradiction shows that i != sqrt(-1), that was the fucking goal.
I INTENTIONALLY assumed i = sqrt(-1) just to show where this assumption fails.
This is called proof by contradiction. Look it up.

>>26
See how in your calculation you never used i=sqrt(-1)?
That's exactly why they don't fall into the trap I explained. The contracdiction only appears when you falsely assume i=sqrt(-1), which I wanted to show is false.

>>29
oh, ok.
sorry for the misunderstanding.
I just woke up so my brain isn't exactly at maximum operation yet.

>>30
Ok, got a bit worked up here as well. Sorry mate
I take
>>28
back

>>31
I hold nothing against you.
I would be angry as well if you stated something as retarded as i did.
In the end though everything worked out, so water under the bridge?

>>30
i^2 = sqrt(i^2) * sqrt(i^2).
i^2 = -1
therefore
i^2 = sqrt(-1).
right?

>>1
How long does the dopamine rush last when you keep pretending to be a special snowflake with a personality disorder that is absolutely 100% the same as any tumblr kid who craves to have something wrong with them to complain about or get attention for?

>>34
Yeah, but how long does it take for piss to land on balls?

>>35
You see a shirt you want to buy that costs $97. You don't have enough money to buy it so you borrow $50 from mom and $50 from dad. You buy the shirt and have $3 left over. You give $1 to your mom and $1 to your dad and $1 for yourself. You now owe them $49 each. 49 + 49 = 98. Plus your $1 = $99. Where'd the extra dollar go?